\[ \int_{0}^{\pi/2} \frac{dx}{5 + 4 \sin^2 x} \]
1
Divide by cos²x
We transform the integral by dividing numerator and denominator by cos²x:
\[ \frac{1}{5 + 4\sin^2x} = \frac{\sec^2x}{5\sec^2x + 4\tan^2x} = \frac{\sec^2x}{5 + 9\tan^2x} \]
2
Substitution Magic
Let t = \tan x, then dt = \sec^2x dx.
When x = 0, t = 0
When x = \pi/2, t \to \infty
The integral transforms to:
\[ \int_{0}^{\infty} \frac{dt}{5 + 9t^2} \]
3
Factor Out Constants
We factor out 9 from the denominator:
\[ \frac{1}{9} \int_{0}^{\infty} \frac{dt}{\frac{5}{9} + t^2} \]
4
Standard Integral Form
We recognize the standard form:
\[ \int \frac{dt}{a^2 + t^2} = \frac{1}{a} \tan^{-1}\left(\frac{t}{a}\right) + C \]
Where a^2 = \frac{5}{9}, so a = \frac{\sqrt{5}}{3}
5
Evaluate the Integral
Applying the standard form:
\[ \frac{1}{9} \times \frac{1}{\sqrt{5}/3} \left[ \tan^{-1}\left(\frac{t}{\sqrt{5}/3}\right) \right]_{0}^{\infty} \]
\[ = \frac{1}{3\sqrt{5}} \left( \frac{\pi}{2} - 0 \right) \]
The Magical Final Answer:
\[ \frac{\pi}{6\sqrt{5}} \approx 0.2342 \]